c# to arduino

Completed Posted Jan 26, 2015 Paid on delivery
Completed Paid on delivery

connect C# and arduino via IP. very simple gui. just have to on LED for my project.

Arduino C# Programming

Project ID: #7033116

About the project

7 proposals Remote project Active Jan 27, 2015

Awarded to:

hunghm08

Design windown Form and using TCP/IP connect board via Ardunio... In addition to LED driver I can control replay, so, taking data from sensors such sensors, the sensor (PIR sensor), ..

$25 SGD in 1 day
(1 Review)
0.2

7 freelancers are bidding on average $27 for this job

XeeChaun

hi. I have 2 years experience in C#. I have worked a lot with TCP/IP sockets. I have also interfaced a lot of hardware modules e.g. GSM, GPS, smart card readers, barcode readers, printers, microcontrollers etc. I'm ver More

$50 SGD in 3 days
(67 Reviews)
6.5
pranavsharma2504

Hi, there! I'm Pranav here, from India. I just read the project description about you wishing to invite some help with connecting your Arduino to a C# application. I was wondering whether you have a wired conne More

$30 SGD in 1 day
(5 Reviews)
3.1
tatulea

Hello! I am Gabriel and I am working with Arduino for 3 years. I already have an IoT project and I will be happy to help you too. Please, give me a p.m. with more details about your project and I will send you a free d More

$21 SGD in 3 days
(0 Reviews)
0.0
alexpod100

Done many simple projects like this, outside of freelancer, also already have a program that does the requiered thing(with Ethernet Shield + Arduino)

$26 SGD in 1 day
(0 Reviews)
0.0
coolankitpandey

Hi , I would like to help you on this . I am working for embedded systems design and development. I am a little new to freelancers but still wanna work and learn more for a very minimal price . Thanks

$16 SGD in 1 day
(0 Reviews)
0.0
abhisheksgtt

I am an electronics hobbyist and I have much experience with arduino and interfacing it with any device. I know c#, visual basic and visual c++. I can do it for sure.

$19 SGD in 2 days
(0 Reviews)
0.0