ingenico developer

Closed Posted 4 years ago Paid on delivery
Closed Paid on delivery

Looking to hire someone preferably in Kenya to develop an application on an Ingenico Move 5000 terminal. Anyone with experience on developing and deploying applications on Ingenico terminals.

More details will be provided.

C Programming C# Programming Java Payment Gateway Integration PHP

Project ID: #19786059

About the project

7 proposals Remote project Active 4 years ago

7 freelancers are bidding on average $2493 for this job

sapotacorp

Hello egift, We have read your project details and we are very much interested to work with you Best regards, Su

$2675 USD in 30 days
(816 Reviews)
8.7
mingxiao2008

Hello, Dear How are you? I have read your project description and am ready for discussing with you about project. I have experienced in developing C Programming, C# Programming, Java, Payment Gateway Integration, P More

$2000 USD in 30 days
(100 Reviews)
8.2
goalscoreplayer

Hi! How do you do! I have read your project description fully. I can understand and finish it wonderfully. I have 8+ years of experiences in .NET/C/C++/JAVA programming. I guarantee high project development and qual More

$2250 USD in 7 days
(48 Reviews)
7.3
adampohp79

Hi. thanks for your posting. I'm very happy to have a chance of bidding your project. I have experience in development of the projects like yours If you hire me, I'll do my best for your project and finish greatly in a More

$2250 USD in 7 days
(51 Reviews)
5.9
adicoman

Hi, I am very interested to work on your project. I have 17+ years experience in Web Development using a large variety of programming languages, frameworks, database architecture, APIs, CRMs, ERPs, mobile development More

$3000 USD in 25 days
(58 Reviews)
5.8
mostafahussiny

I have 8 years experiance in developement on ingenico terminals Unicapt32, telium2, telium3 (tetra) I worked on move 2500 and move 5000 Also worked on newland, wizarpos android, mobiwire I developed banking appli More

$2777 USD in 30 days
(0 Reviews)
0.0